Yawyaw. I would like to ask you how works the de Broglie oscillation in the quaternion theory?.
There is a repulsive energy according to Pauli exclusion principle and gravitational attractive warping of the space. That way the matter interacts repulsive and attractive.
If so, that was my point, and you refute you claim that "The mathematics was compromised to satisfy physics dogma".
My work relates Planck's Constant h to the fine structure constant thru z, the free space impedance. z=W/C =375 Ohms and h=WC where W= 500 atto Webers (volt second) and C=4/3 E-18 (atto) Coulombs. The Ether Vacuum has quantum and magnetic charges, C and W. h=zC^2.
The Fine Structure Constant alpha=1/2 (e/C)^2/n . This may help.
Off Topic.It is still the rule in physics that a displacement in the direction of the force is still called energy. The reason is that around 1900, Oliver Heaviside and J, Willard Gibbs listened to the physicists
My undergraduate physical chemisty professor used to include a bonus question on the final exam to reduce the failure rate or to entertain himself.
He'd post a picture and ask: Who is this?
It was J. Willard Gibbs, the inventor of Physical Chemistry.
Last edited by John Jones; 2008-Apr-30 at 02:23 AM.
X^2 = ((d^2/c^2dt^2 - Del^2) + 2d/dR Del) The wave equation for Gravity is a quaternion and consists of a real part and a vector part: a real longitudinal wave equation and a vector Transverse wave equation. The
X^2E= ((d^2/c^2dt^2 - Del^2)(-mu/R) -2mcd/dR Del.v) + ((d^2/c^2dt^2 - Del^2)mcv + 2d/dR(mcDelxv + Del(-mu/R))
x^2E = ((d^2/c^2dt^2 - Del^2)(-mu/R) + 2mcvcos(g)/R^2) + ((d^2/c^2dt^2 - Del^2)mcv + 2mv(csin(g)/R^2 + v r/R3))
Here you see the Quaternion wave equations, a real longitudinal wave and the vector transverse wave. At the equilibrium condition, 0=XE, the waves are simplified.
X^2E = -(d^2/c^2dt^2 + Del^2)(-mu/R + mcv).
Last edited by yawyaw; 2008-Apr-30 at 04:38 AM.
But you said: "It appears that for Relativity Theory, the 4-vector is a QUATERNION... "
So I asked whether - according to you - the formulation of Relativity in terms of quaternions is equivalent to the formulation in terms of four-vectors.
Of course, you are utterly wrong when you finish the sentence with "and not the Minkowski 4-vector elsewhere", since the "Einstein" space-time interval you quoted is at the basis of the definition of Minkowskian vector-space.
So, where is it? I see only squares of real numbers.
Please can you tell me what "R" is in
Originally Posted by yawyaw
I claim that Gravity is described by a classical quaternion energy E= -mu/R + mcv.
as always it has to be to make it work.
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for example d/dR(-mu/ct) = d/cdt (-mu/ct)= -mu/c2d/dt 1/t=mu/(ct)2 = mu/R2
The derivative would be the time derivative rather than the space derivative. Spacetime has space units thus ct=meters. Space and Time came before spacetime. Much of physics is still in that mode. For example electromagnetism uses space and time in maxwell's Equations: Faraday's law: 0= dBv/dt + DelxE Del is a space derivative. My version is 0= dEv/dR + DelxEv= dEv/cdt + DelxEv. This shows that Bv = Ev/c.
This is like saying the distance to the sun from earth is 150 Giga meters or 500 light seconds(ct=c500).
But that is not time, that is space. I can talk about distances in terms of light seconds, and in essence that is what we do if we use the convention where we set c=1. That still doesn't mean that in a particular inertial frame we can just replace spatial derivatives by time derivatives. Do you really believe that for a function f, you can writeRadar time gives the best reasoning model, or light year. distance. I generally use R because it reflects that I am working with distances, in calculus. Think of R as 500 seconds out as a distance. I think of the sun as 8 1/3 minutes away.
df/dR = (1/c)df/dt ?
The left hand side is the rate of change of f with respect to a spatial displacement, whereas the righthand side is a rate of change with respect to time.