Re: Theory of Relativity Question
No. You are thinking logically, which does not work. The important aspect of special relativitiy is light's speed can only be observed to be one speed regardless of any other motion.
Originally Posted by thunderchicken
You assumed it would take more time for the light to have traveled to the mirror from the viewpoint of the non-spaceship observer. Let's consider first the distance only involved. The distance vertically (as seen by the spaceman) we'll call... d. The distance the light travelled as seen by the observer....d'. The spaceship traveled a certain distance as seen by the observer.....d'2, but this is simply the velocity of the ship times the time the observer saw it move, therefore, it can be stated as .....vt'.
These three distances form a right triangle. d'^2 = (vt')^2 + d^2
But d' = ct' and d = ct. Substitute and solve for t'.
This site is quite helpful.... here
This shows that time is not the same for both observers.
We know time flies, we just can't see its wings.