Originally Posted by

**Lunatik**
If v = fL (where L is light wavelength), and v = c, then f = v/L = c/L. Now, if c is greater in deep space than what we measure in Earth's 1 AU, then c' > c, so that if f'= c'/L' for v' = c', then it should follow that f' = f, which means there should be no change in cosmic light frequency. Only the wavelength changes, but the frequency remains the same, so spectral analysis is not affected. The difference is that for any given frequency, wavelength L' shifts to the red, i.e., redshift of cosmic light. This is due to the fact that if light travels a greater distance, per v' = d'/t, its wavelength is stretched out. I am also assuming that contrary to SR, t' = t always, though we cannot observe it this way from where we sit.

The idea here is that deep space gravity, if greater out there than here, light should travel faster, cover greater distance, than here, but blueshift back to our known values once it enters the inner solar system where gravity is weaker. This is based on a speculative assumption that closer to a hot radiant star means lower gravity (per mass) than farther from star, where gravity (as expressed in the proportional of G) is greater.

Therefore, if spectral analysis of distant cosmic light is taken from deep space, at multiple AUs from Earth's, that redshift should appear to be greater for the same spectral analysis of such light frequency as now found from Earth's ~1 AU observations. In fact, this redshift should be more deeply redshifted if measured from Cassini, at about 9.5 AU, for example, but relatively blueshifted back (to our known redshift values) when again observed from Earth's location. This test could be done from existing spacecraft already far out in the solar system, if the probes instruments can be directed to do this.