Surely a parallax measurement would be the same for either observer whether stationary or travelling near c. Why would movement change the triangulation?
Moved from here: http://www.bautforum.com/showthread....-maximum-speed
Surely a parallax measurement would be the same for either observer whether stationary or travelling near c. Why would movement change the triangulation?
Moved from here: http://www.bautforum.com/showthread....-maximum-speed
Last edited by pzkpfw; 2012-Jun-26 at 07:19 PM. Reason: Add note
Yes. That is what I said (or intended to). You measure the baseline and the angles, calculate the distance: the "stationary" observe calculates 22 ly; the moving one calculates 1 ly. They measure the same baseline but different angles (because the distance to the object is different).
But like I said, for that to happen either the lateral movement against the background stars would need to contract or the distance between the viewpoints, but that is not possible as that is not the direction of travel.
Look at the method used.
1.Distance is measured between viewpoints = real number
2.Lateral movement is measured = real number
3.Angles determined = derived from 1 & 2
4.Distance calculated = derived from 1, 2 & 3
1 & 2 are the only real measurement hence only they can cause differences in the angle and distance. How can forward movement affect those first 2 measurements?
The problem is anything but an exact 90 degrees has a contraction as part of its vector.
Let me try to explain what I see: (difficult because of my lack of correct terminology)
To judge speed, you are taking a time measurement between two objects or positions at two different times. No matter which object you choose as your 90 degree angle, the measurement at the other time point has changed it's angle and introduces contraction.
Which means that the stationary observer would have the target star in one particlular position on a photographic plate when compared to the background, and the moving observer would have the target star in a different position on the photographic plate when compared to the background as it passed virtualy the same point in space. Not sure how that is possible.
Good point NEOWatcher.
Webbo, are you thinking that length contraction only happens in exactly the direction of travel?
As a crude analogy, think of taking two photographs from different distances but with different focal length cameras such that the main object in the picture appears the same size in both. Other objects will have a different spatial relationship in the two images because one is "compressed" in the direction the picture is taken.
Similarly, the travelling observer will see everything "squished" which will change their apparent relationships.
Ah, I think I see (maybe). You are considering the displacement and the baseline as both being at right angles to the direction of travel? But the displacement is a result of the trigonometry of the setup; i.e. the angle between two different viewpoints looking at the same object.
The angles to the star (which you are measuring as a displacement) are between lines in the direction of travel (which will be shorter) and a line orthogonal to the direction of travel (which will not be shorter).
Do I need to draw a diagram, I wonder... (ETA: no need!)
For the travelling observer, the distance being measured (indirectly) is shorter and therefore the angle/displacement must be greater.
Since length contraction is only in the direction of movement the angles are different.
Parralax2.png
Actually a better representation would be
as the observers would be using the angles F & E to derive the distance of C & D
I'll add that both ships at the tips can tell that they are travelling parallel to each other and trade data to get the parallax (purple lines is the direction of motion of the observers)
Just to clarify. If everything is squished then the arc second must also be squished hence measurements would be exacly the same. What's required is for just the target star to be slightly shifted compared to the background.
No
triangles.png
Those 2 triangles where identical before I squashed one of them. Angle A ≠ B. This is basic euclidean geometry
Ah wait. I think I know where you are getting confused. An obserer will not agree with an observer, in a different inertial frame, on the angular separation of 2 objects. This is why the accelerated observer will come up with a different parallax measurement then the non accelerated obsserver.
If the camera takes an image of say the forward hemisphere and everything is squished then there will be an empty band around the outside. Only an inept scientist would continue to use the empty band as part of the total arc measurement. If an area of the photo is squished, then the unit of measurement must also be squished.
There is no empty band.
In this image the left one is a stationary observer.
The right one is an accelerated observer.
arc.png
The accelerated observer will see a larger angular distance between the 2 objects then the non accelerated observer. The closer an object is to the direction of travel the more it will have its distance contracted. They can still see a continuous 360 degrees around them. The objects in front of them look a lot closer, the objects perpendicular to their direction of motion seem to be the same, objects directly behind them seem to be very far away. Through out the entire 360 degrees it is a completely smooth transition
Perhaps you could do some simple drawing on what you think is happening. Notice I've squished the 2 red dots but I haven't squished the sphere around the observer. This is why the parallax angle changes.
So you are saying the stars in front are squashed together but perpendicular are the same. Which means at somewhere between the 2 points there must be larger than expected gaps. I would argue that such a distortion should not be measured using fixed arcseconds. Any attempt to do so would be scientifically inept.
Fair enough. this thread topic is about speed, and to determine speed you need a distance, so the lines got a little blurred. But the concept still applies...
Even removing time from the equation, you are still talking about 3 points in space. Unless they are a straight line, there will be at least one angle that is not 90 degrees from the direction of travel. Therefore, contraction can not be removed from the equation.
No, there is no empty band until you reach c itself where a photon can't "catch up" to you. The "squish" is non-uniform around the field of view. It gets more compressed as you look forward, and less compressed as you look back. The distortion does not exist at 90 degrees and gets more "squished" as you look forward. As you go from 90 to 180, the field of view is stretched.
Why? A spherical coordinate system is a spherical coordinate system. There isnt any requirement that the distribution of stars be distributed in any specific way. The universe is distorted at relativistic velocities. Changing the coordinate system to make it look 'normal' wouldnt be useful