I don't have the exact figures at hand, but this is surely a much higher density than the shuttle tiles. Now, how thick must it be applied to get the same protection? And I really see the problem with getting this stuff fixed to the skin good enough to survive the launch and being easily enough replaceable after landing.
Harald
PS: Found some figures:
http://chemed.chem.purdue.edu/demos/...eets/13.4.html
Density 9 lb/ft^3
That's (sorry, I'm metric) 4082gr/28316cm^3= 0.145gr/cm^3
Aluminum has some 2.7gr/cm^3, so said material must have around 0.67gr/cm^3
That's 4.6 times more dense than the shuttle tile material.