
Originally Posted by
cjl
Not necessarily. The Schwarzschild radius of a black hole is proportional to its mass (Rs = 2GM/c2). However, the volume enclosed is proportional to the radius cubed. With some rearrangement, you can see that the density required (assuming a uniform, isotropic sphere) to collapse into a black hole is proportional to 1/M2, so the more mass a sphere contains, the less density is required for it to become a black hole.
Because of this, a uniform collapsing sphere will reach the density at which it will become a black hole before any regions within the sphere will reach their critical densities. Basically, at the point at which the entire core can become a black hole, a small portion of the center is quite far from being dense enough to be a black hole on its own. So, rather than starting as a small black hole in the middle of the core and growing, the black hole will in essence form all at once, with the entire mass of the core contained (and will therefore not evaporate immediately).